Asked by BlubBlub
The diffusion constant for the alcohol ethanol in water is 1.24x10^-9 m2/s. A cylinder has a cross-sectional area of 4.10 cm^2 and a length of 2.06 cm. A difference in ethanol concentration of 1.37 kg/m^3 is maintained between the ends of the cylinder.
In one hour, what mass of ethanol diffuses through the cylinder?
In one hour, what mass of ethanol diffuses through the cylinder?
Answers
Answered by
Damon
well, I will try to do dimensional analysis because I have no idea.
constant * cross sectional area
inversely proportional to length
1 hr = 3600 s
4.1 cm^2* 1m^2/10^4 cm^2 = 4.1*10^-4 m^2
Q = k * A/L * delta c * time
try
Q = 1.24*10^-9 m^2/s * 4.1*10^-4 m^2 /.0106 m * 1.37 kg/m^3 * 3600 s
gives kilograms in an hour
constant * cross sectional area
inversely proportional to length
1 hr = 3600 s
4.1 cm^2* 1m^2/10^4 cm^2 = 4.1*10^-4 m^2
Q = k * A/L * delta c * time
try
Q = 1.24*10^-9 m^2/s * 4.1*10^-4 m^2 /.0106 m * 1.37 kg/m^3 * 3600 s
gives kilograms in an hour
Answered by
Jordan
Damon was close.
m= (DAΔC)t/L = 1.24e-9*4.10e-4*1.37*3600/2.06e-2
= 1.217e-7
m= (DAΔC)t/L = 1.24e-9*4.10e-4*1.37*3600/2.06e-2
= 1.217e-7
Answered by
BlubBlub
THANK YOU!!!!
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