Asked by Rose
A medicine in the bloodstream has a concentration of c(t) =at/t^2 + b where a=3 and b=1
Approximate the highest concentration of the medicine reached in the bloodstream
Find algebraically when c(t) less then Sign 0.5
Approximate the highest concentration of the medicine reached in the bloodstream
Find algebraically when c(t) less then Sign 0.5
Answers
Answered by
Bosnian
The question does not make sense.
a t / t ^ 2 =
3 t / t ^ 2 =
3 t / ( t * t ) =
3 / t
a t / t ^ 2 + b =
3 t / t ^ 2 + 1 =
3 / t + 1
Tends to infinity as x tends towards 0.
a t / t ^ 2 =
3 t / t ^ 2 =
3 t / ( t * t ) =
3 / t
a t / t ^ 2 + b =
3 t / t ^ 2 + 1 =
3 / t + 1
Tends to infinity as x tends towards 0.
Answered by
Rose
How would i approximate the highest concentration reached in the bloodstream
Answered by
Bosnian
Not at all.
highest concentration = infinity as x tends towards 0.
highest concentration = infinity as x tends towards 0.
Answered by
Rose
The question also states to determine how long it takes for the medicine to drop below 0.2 how could i do this
Answered by
Reiny
Rose, it was pointed out to you by Bosnian that your question makes no sense, yet you keep asking questions pertaining to it.
your equation is
c(t) = 3t/t^2 + 1
which reduces to
c(t) = 3/t + 1
Even at the beginning, when t=0, this would be undefined.
That is, the concentration would be infinitely huge, rather silly, don't you think?
the graph looks like this:
http://www.wolframalpha.com/input/?i=plot+y+%3D+3%2Fx+%2B+1
As t gets larger, c(t) will approach 1
for c(t) < .5
3/t < .5
3 < .5t
t > 6
the graph confirms this
your equation is
c(t) = 3t/t^2 + 1
which reduces to
c(t) = 3/t + 1
Even at the beginning, when t=0, this would be undefined.
That is, the concentration would be infinitely huge, rather silly, don't you think?
the graph looks like this:
http://www.wolframalpha.com/input/?i=plot+y+%3D+3%2Fx+%2B+1
As t gets larger, c(t) will approach 1
for c(t) < .5
3/t < .5
3 < .5t
t > 6
the graph confirms this
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