Question

a capacitance of 6microfarad and another unknown capacitance are connected in series to a battery, if the potential difference between the battery terminals is 16v while over the unknown capacitance is 6v, find the magnitude of the unknown capacitance, the total energy furnished by the battery and the total energy in the charged capacitance

Answer 1

C = Q/V so V = Q/C
Vk = 10
Vu = 6

Q the same on both
so
10 = Q/6*10*-6
Q = 6*10^-5 coulombs

6 = 6*10^-5 /Cu
Cu = 10^-5 farads = 10 microfarad

energy = (1/2) Q V for each

Answer 2

What about the third one that is the total energy furnished