If 5.026g chromium is combined with 3.04L of chlorine gas at 0.955atm

Question

and 220C, what mass of chromium (III) chloride is produced?

Answer 1

PV=nRT
n=PV/RT

Pressure (0.955atm), Volume (3.04L), R constant (0.082), Temperature (273 + 220 = 493 K).

n = 2.9032/40.426
= 0.071815 moles