Asked by Cameron
a see saw is balanced. left hand side is 3m long and has an applied force of 4N
the righth hand side is 6m long and has an unknown force applied. what is that force?
the righth hand side is 6m long and has an unknown force applied. what is that force?
Answers
Answered by
Henry
F2*d2 = F1*d1.
F2*6 = 4*3 = 12.
F2 = 2 N.
F2*6 = 4*3 = 12.
F2 = 2 N.
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