Asked by asd

The sum of all five terms of an arithmetic sequence is
55. Find the sum of the first three terms of the sequence if the sum of the last three is 48.

Answers

Answered by Steve
S5 = 5/2 (2a+4d)
S2 = 2/2 (2a+d)
The sum of the last 3 is S5-S2, so we have
S2 = 55-48 = 7 = 2a+d

2a+d = 7
5/2 (2a+4d) = 55

a=1, d=5

So, S3 = 3/2 (2+2*5) = 18
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