Question
the driver of a car travelling at 100km/hr suddenly sight an obstacle 50m ahead of him What maximum acceleration must be applied to the car by applying the brake in order to avoid hitting the obstacle
Answers
100 km/hr = 27.78 m/s
v = √(2as)
27.78 = √(100a)
a = 7.716 m/s^2
That is the minimum acceleration which will do the job. There is no maximum value.
v = √(2as)
27.78 = √(100a)
a = 7.716 m/s^2
That is the minimum acceleration which will do the job. There is no maximum value.
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