Asked by Anonymous

Find coordinates of the points on the given curve at which it's gradient has the given value.

Y=x^3+x^2
Gradient = 1

I know that
dy/dx = 3x^2+2x

I'm not sure what to do next.

Please help
Thankyou 😘
Answered by Damon
Well, when is that slope equal to 1 ?

3 x^2 + 2 x - 1 = 0

(3x-1)(x+1) = 0

x = 1/3 or x = -1
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