Asked by Anonymous
                Find coordinates of the points on the given curve at which it's gradient has the given value.
Y=x^3+x^2
Gradient = 1
I know that
dy/dx = 3x^2+2x
I'm not sure what to do next.
Please help
Thankyou 😘
            
        Y=x^3+x^2
Gradient = 1
I know that
dy/dx = 3x^2+2x
I'm not sure what to do next.
Please help
Thankyou 😘
Answers
                    Answered by
            Damon
            
    Well, when is that slope equal to 1 ?
3 x^2 + 2 x - 1 = 0
(3x-1)(x+1) = 0
x = 1/3 or x = -1
    
3 x^2 + 2 x - 1 = 0
(3x-1)(x+1) = 0
x = 1/3 or x = -1
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.