Question
The length of the rectangle 5cm more than twice the width.The perimeter is 70.What is the area?
Answers
Bosnian
The length of the rectangle 5cm more than twice the width.
This mean :
L = 5 + 2 W
P = 2 W + 2 L = 2 ( W + L )
70 = 2 ( W + L )
70 = 2 ( W + 5 + 2W )
70 = 2 ( 3 W + 5 ) Divide both sides by 2
70 / 2 = 2 ( 3 W + 5 ) / 2
35 = 3 W + 5 Subtract 5 to both sides
35 - 5 = 3 W + 5 - 5
30 = 3 W Diwide both sides by 3
30 / 3 = 3 W / 3
10 = W
W = 10 cm
L = 5 + 2 W = 5 + 2 * 10 = 5 + 20 = 25 cm
Proof :
P = 2 ( W + L ) = 2 ( 10 + 25 ) = 2 * 35 = 70 cm
This mean :
L = 5 + 2 W
P = 2 W + 2 L = 2 ( W + L )
70 = 2 ( W + L )
70 = 2 ( W + 5 + 2W )
70 = 2 ( 3 W + 5 ) Divide both sides by 2
70 / 2 = 2 ( 3 W + 5 ) / 2
35 = 3 W + 5 Subtract 5 to both sides
35 - 5 = 3 W + 5 - 5
30 = 3 W Diwide both sides by 3
30 / 3 = 3 W / 3
10 = W
W = 10 cm
L = 5 + 2 W = 5 + 2 * 10 = 5 + 20 = 25 cm
Proof :
P = 2 ( W + L ) = 2 ( 10 + 25 ) = 2 * 35 = 70 cm