Question
Engine oil (η = 0.20 Pa⋅s) passes through a fine 2.60-mm-diameter tube that is 8.60 cm long. What pressure difference is needed to maintain a flow rate of 7.8 mL/min ?
So what i did was
(7.8Ee-3 /60) = π P (1.3e-3) ^4 /(8* 0.086*0.2)
I get 1.99E5 but its not right, im not sure what im doing wrong
So what i did was
(7.8Ee-3 /60) = π P (1.3e-3) ^4 /(8* 0.086*0.2)
I get 1.99E5 but its not right, im not sure what im doing wrong