To determine which graph matches the linear equation \( 6x + y = -4 \), we can rearrange the equation into slope-intercept form (y = mx + b) or evaluate it at the given points.
First, let's isolate \( y \) in the equation:
\[ y = -6x - 4 \]
Now, we can check the given points to see if they satisfy the equation.
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For \( (0, 2) \): \[ y = -6(0) - 4 = -4 \quad \text{(not (0, 2))} \]
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For \( (1, -1) \): \[ y = -6(1) - 4 = -10 \quad \text{(not (1, -1))} \]
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For \( (3, 0) \): \[ y = -6(3) - 4 = -22 \quad \text{(not (3, 0))} \]
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For \( (0, -2) \): \[ y = -6(0) - 4 = -4 \quad \text{(not (0, -2))} \]
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For \( (0, -4) \): \[ y = -6(0) - 4 = -4 \quad \text{(matches)} \]
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For \( (1, -10) \): \[ y = -6(1) - 4 = -10 \quad \text{(matches)} \]
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For \( (1, 2) \): \[ y = -6(1) - 4 = -10 \quad \text{(not (1, 2))} \]
After evaluating the points, we see that \( (0, -4) \) and \( (1, -10) \) satisfy the linear equation \( 6x + y = -4 \).
Thus, the graph that matches the equation must include the points \( (0, -4) \) and \( (1, -10) \).