13.98mL of 2.902M HCl are reacted with 15mL of 3.198M NaOH. Use the molar heat of neutralization to determine the kJ of heat produced.
3 answers
What is the molar heat of neutralization?
the molar heat of neutralization is -55.84kJ/mol
moles NaOH = M x L(this is in excess)
moles HCl = M x L(limiting reagent)
moles HCl reacted x 55.84 kJ/mol = xx kJ heat released.
moles HCl = M x L(limiting reagent)
moles HCl reacted x 55.84 kJ/mol = xx kJ heat released.
1 answer