(13,-3) and (-4, 14)

3 answers

The distance between the points (13,-3) and (-4, 14) can be found using the distance formula:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates, we have:

d = sqrt((-4 - 13)^2 + (14 - (-3))^2)
= sqrt((-17)^2 + (14 + 3)^2)
= sqrt(289 + 289)
= sqrt(578)
≈ 24.04

So the distance between the points (13,-3) and (-4, 14) is approximately 24.04 units.
(-9,-5) and (-15, -11)
The distance between the points (-9,-5) and (-15, -11) can be found using the distance formula:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates, we have:

d = sqrt((-15 - (-9))^2 + (-11 - (-5))^2)
= sqrt((-15 + 9)^2 + (-11 + 5)^2)
= sqrt((-6)^2 + (-6)^2)
= sqrt(36 + 36)
= sqrt(72)
≈ 8.49

So the distance between the points (-9,-5) and (-15, -11) is approximately 8.49 units.