Asked by jj
12y−2x=12
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Answered by
GPT-4o mini
To solve the equation \( 12y - 2x = 12 \) for one variable in terms of the other, let’s isolate \( y \).
1. Start with the equation:
\[
12y - 2x = 12
\]
2. Add \( 2x \) to both sides:
\[
12y = 2x + 12
\]
3. Now, divide every term by \( 12 \):
\[
y = \frac{2x + 12}{12}
\]
4. Simplify the right side:
\[
y = \frac{2x}{12} + \frac{12}{12} = \frac{x}{6} + 1
\]
So, the equation can be rewritten as:
\[
y = \frac{x}{6} + 1
\]
If you need to solve for \( x \) in terms of \( y \), you can do the following:
1. Start with the original equation:
\[
12y - 2x = 12
\]
2. Rearrange it to isolate \( x \):
\[
-2x = 12 - 12y
\]
3. Divide by \( -2 \):
\[
x = 6y - 6
\]
Thus, \( x \) can be expressed as:
\[
x = 6y - 6
\]
You can use either form depending on which variable you want to express in terms of the other.
1. Start with the equation:
\[
12y - 2x = 12
\]
2. Add \( 2x \) to both sides:
\[
12y = 2x + 12
\]
3. Now, divide every term by \( 12 \):
\[
y = \frac{2x + 12}{12}
\]
4. Simplify the right side:
\[
y = \frac{2x}{12} + \frac{12}{12} = \frac{x}{6} + 1
\]
So, the equation can be rewritten as:
\[
y = \frac{x}{6} + 1
\]
If you need to solve for \( x \) in terms of \( y \), you can do the following:
1. Start with the original equation:
\[
12y - 2x = 12
\]
2. Rearrange it to isolate \( x \):
\[
-2x = 12 - 12y
\]
3. Divide by \( -2 \):
\[
x = 6y - 6
\]
Thus, \( x \) can be expressed as:
\[
x = 6y - 6
\]
You can use either form depending on which variable you want to express in terms of the other.
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