12kg box is placed on a rough surface. A force of 20N is applied at an angle of 30 degrees. Calculate the magnitude and direction of the normal and friction forces

Answer 1

if no one has answered this question yet, that is means the question is difficult. So i will try if i know. I think the answer is 62

Answer 2

The normal force is always perpendicular to the surface. So if the box is on a horizontal surface the Normal force it will be equal to the weith of it (mass *gravity)
N= m*g N=117.6N the friction force always oposses to the movement and it will be equal to the horizontal component of the force that is F Cos 30º
Fr= 20N*Cos 30 = 17.32 N