Question

If 5x4-14x³+18x²+40x+16=(x²-4x+8)(ax²+bc+c) find a,b and c and hence find the four solutions of the equation 5x4-14x³+18x²+40x+16


Given that x³-1=(x-&)(ax²+bx+c) find the values of a,b and c and hence find the three roots of the equation x³=1
{These three roots can be referred to as 'the cube roots of unity' and are often written as 1, w, w²}