Asked by jay
Find the first order partial derivatives. z=ln(xy-sqrt(x^2-y^2)
Answers
Answered by
Steve
so, do you mean
ln(xy-sqrt(x^2-y^2))
or
ln(xy)-sqrt(x^2-y^2)
I will assume the first, since the 2nd is much easier
∂z/∂x = 1/ln(xy-√(x^2-y^2)) * (y-x/√(x^2-y^2))
and similarly for y.
ln(xy-sqrt(x^2-y^2))
or
ln(xy)-sqrt(x^2-y^2)
I will assume the first, since the 2nd is much easier
∂z/∂x = 1/ln(xy-√(x^2-y^2)) * (y-x/√(x^2-y^2))
and similarly for y.
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