Asked by elle
hi, just wondering on how i should approach differentiating: loge1/(3-x)^5
can i differentiate it as loge(3-x)^5?
sorry i meant to write (3-x)^-5
Hmmmm.
You are haveing a brain seizure. Watch this:
Ln x^-a= - ln x^a= -a ln x
Amazing.
So loge1/(3-x)^5= -5 ln(3-x)
Check my thinking.
can i differentiate it as loge(3-x)^5?
sorry i meant to write (3-x)^-5
Hmmmm.
You are haveing a brain seizure. Watch this:
Ln x^-a= - ln x^a= -a ln x
Amazing.
So loge1/(3-x)^5= -5 ln(3-x)
Check my thinking.
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