Asked by maria
A person drive an automobile with a mass of 450 kilograms at a velocity of 26 meters per second. The driver accelerates to a velocity of 30 meters per second. The difference in the automobile's kinetic energy is how many joules?
Answers
Answered by
Henry
KE2-KE1 = 0.5M*V2^2 - 0.5M*V1^2 =
0.5*450*30^2 - 0.5*450*26^2 = 202,500 -
152,100 = 50,400 J.
0.5*450*30^2 - 0.5*450*26^2 = 202,500 -
152,100 = 50,400 J.
Answered by
Deez nuts
Got eeeem
Answered by
Jigahdee
The answer is 202500
Answered by
Jigahdee
Sorry, my mistake... It is 50,000 J. :)
Answered by
Anonymous
A person drives an automobile with a mass of 450 kilograms at a velocity of 26 meters per second. The driver accelerates to a velocity of 30 meters per second.
Answered by
Taj
334555
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