Asked by Jack
How can you completely factor the following polynomial:
6x^5-51x^3-27x
6x^5-51x^3-27x
Answers
Answered by
Steve
clearly the 1st step is to factor out 3x:
3x(2x^4-17x^2-9)
Then you have a quadratic in x^2, which you can factor with a little work, to get
3x(x^2-9)(2x^2+1)
The x^2-9 is easy, giving
3x(x-3)(x+3)(2x^2+1)
3x(2x^4-17x^2-9)
Then you have a quadratic in x^2, which you can factor with a little work, to get
3x(x^2-9)(2x^2+1)
The x^2-9 is easy, giving
3x(x-3)(x+3)(2x^2+1)
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