Asked by Coly
The width of a rectangular box is twice the height. Twice the length of the box exceeds the sum of the width and the height by 5in. Given that the sum of the length, width, and height is 16in, find the length, width, and height.
I got,
w=2h
2L=w+h+5
L+w+h=16
I don't know if the problems are right. I would like to know if they are or not. I can do the rest of the problem, I'm just unsure if I got the right problems out of the story problem.
I got,
w=2h
2L=w+h+5
L+w+h=16
I don't know if the problems are right. I would like to know if they are or not. I can do the rest of the problem, I'm just unsure if I got the right problems out of the story problem.
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