Given that 2<=f(x)<=3 for -5<=x<=1, use a property of definite integrals to find an interval in which the value of interval sign{-5}^{1} f(x)dx lies.

Answer 1

since 2 <= f(x) <= 3, and the width of the interval is 6,

2*6 <= ∫f(x) dx <= 3*6