Asked by amanda

plant a produced 8000 fewer panels than plant b, 4 % of the panels from plant a, and 3% of the panels from plant b were defective, how many panels did plant a produce if the two plants together produced 660 defective panels?

Answers

Answered by Reiny
panels produced by plant A --- x
panels produced by plant B = x+8000

defective from A = .04x
defective from B = .03(x+8000)

solve for x:

.04x + .03(x+8000) = 660

(I would get that "caps lock" key fixed on your device)
Answered by george
6000
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