H2A + 2NaOH ==> Na2A + 2H2O
mols NaOH = M x L = ?
Using the coefficients in the balanced equation, convert mols NaOH to mols H2A (that is 1/2 mols NaOH)
Then mols = grams/molar mass. You know grams and mols, solve for molar mass.
A 0.120 g sample of a diprotic acid of unknown molar mass is dissolved in water and titrated with 0.1218 M NaOH. The equivalence point is reached after adding 12.4 mL of base.
What is the molar mass of the unknown acid?
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