A BALL IS PROJECTED VERTICALLY UPWARD FROM THE TOP OF A TOWER 60MITRE HIGH WITH A VELOCITY OF 30MITRE PER SECONDS.WHAT IS THE MAXIMUM HEIGHT ABOVE THE GROUND LEVEL?HOW LONG DOES IT TAKE TO REACH THE GROUND?

Answer 1

a. h = ho + (Vf^2-Vo^2)/2g.
ho = 60 m.
Vf = 0.
Vo = 30 m/s.
g = -9.8 m/s^2.
h = ?

b. Vf = Vo + g*Tr.
Vf = 0.
Vo = 30 m/s.
g = -9.8 m/s^2.
Tr = Rise time.
Tr = ?

b. 0.5g*Tf^2 = h(Part a).
g = 9.8 m/s^2.
Tf = Fall time.
Tf = ?

Tr + Tf = Time to reach gnd.

Answer 2

，105