Asked by Jorge
What is the minimum volume of 2.6 M HBr required to completely dissolve 35.0 g of potassium metal?
Answers
Answered by
DrBob222
.......2HBr + 2K ==> 2KBr + H2
mols K = grams/molar mass
Using the coefficients in the balanced equation, convert mols K to mols HBr.
Now convert mols HBr to volume using
M HBr = mols HBr/L HBr. You know M and mols, solve for L.
mols K = grams/molar mass
Using the coefficients in the balanced equation, convert mols K to mols HBr.
Now convert mols HBr to volume using
M HBr = mols HBr/L HBr. You know M and mols, solve for L.
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