Question
The AM frequencies of a radio dial range from 550 kHz, and the FM frequencies range of 88.0 MHz to MHz. all of these radio waves travel at a speed of 3.0x10^8 m/s, what are the wavelenght ranges of a.) the aM brand b.) FM brand
Answers
Henry
a. AM band:
L1 = V/F = 3*10^8/5.5*10^5 =
L2 = 3*10^8/1.585*10^6
b. FM band:
L1 = V/F = 3*10^8/8.8*10^7 =
L2 = 3*10^8/1.08*10^8 =
L1 = V/F = 3*10^8/5.5*10^5 =
L2 = 3*10^8/1.585*10^6
b. FM band:
L1 = V/F = 3*10^8/8.8*10^7 =
L2 = 3*10^8/1.08*10^8 =
Thabang
f so LG so*8,8645''4-93,6*4,4