Asked by vig
Mr.Mathew left one-fourth of his property to his daughter as well as his son. He also left one-third of the remaining to charity and the rest to his wife. How much did his wife get if the charity amount was 100,000?
Answers
Answered by
Henry
4/4 - (1/4+1/4) = 4/4 - 2/4 = 2/4 = 1/2
Left.
1/2 - 1/3 = 3/6 - 2/6 = 1/6 Left for wife.
(1/6)/(2/6) * 100,000 = 1/2 * 100,000 =
50,000 = Wife's amount.
Left.
1/2 - 1/3 = 3/6 - 2/6 = 1/6 Left for wife.
(1/6)/(2/6) * 100,000 = 1/2 * 100,000 =
50,000 = Wife's amount.
Answered by
Sagnik
No it ha said one third of the remaining . That means after giving 1/2 of his property he divided the remaining amount into a third ie. (1/4 + 1 /4)×1/3. So the answer will be his wife will get rs 200000
Answered by
Rupjit Kalita
Let the property of Mr. Mathews be x.
Since, Mr. Mathews gave his daughter and son equal part of the property, i.e., ¼ to each.
Therefore, left part of the property
= X-[(x/4)+(x/4)]
=X - x/2 = X/2
Now, he gave ⅓ of remaining part of property to charity, i.e., ⅓×[x/2]
=x/6
And, rest part of his property he gave to his wife, i.e., (x/2)-(x/6)
=x/3
Since, the charity amount is Rs. 1,00,000.
Therefore, x/6 = Rs.1,00,000
Or x= Rs.6,00,000
This, total amount property =Rs.6,00,000
Hence, Mr. Mathews's wife gets
= Rs. (6,00,000÷3)
= Rs. 2,00,000.
Since, Mr. Mathews gave his daughter and son equal part of the property, i.e., ¼ to each.
Therefore, left part of the property
= X-[(x/4)+(x/4)]
=X - x/2 = X/2
Now, he gave ⅓ of remaining part of property to charity, i.e., ⅓×[x/2]
=x/6
And, rest part of his property he gave to his wife, i.e., (x/2)-(x/6)
=x/3
Since, the charity amount is Rs. 1,00,000.
Therefore, x/6 = Rs.1,00,000
Or x= Rs.6,00,000
This, total amount property =Rs.6,00,000
Hence, Mr. Mathews's wife gets
= Rs. (6,00,000÷3)
= Rs. 2,00,000.
Answered by
Ashita
Let the property of Mr. Mathews be x.
Since, Mr. Mathews gave his daughter and son equal part of the property, i.e., ¼ to each.
Therefore, left part of the property
= X-[(x/4)+(x/4)]
=X - x/2 = X/2
Now, he gave ⅓ of remaining part of property to charity, i.e., ⅓×[x/2]
=x/6
And, rest part of his property he gave to his wife, i.e., (x/2)-(x/6)
=x/3
Since, the charity amount is Rs. 1,00,000.
Therefore, x/6 = Rs.1,00,000
Or x= Rs.6,00,000
This, total amount property =Rs.6,00,000
Hence, Mr. Mathews's wife gets
= Rs. (6,00,000÷3)
= Rs. 2,00,000.
Since, Mr. Mathews gave his daughter and son equal part of the property, i.e., ¼ to each.
Therefore, left part of the property
= X-[(x/4)+(x/4)]
=X - x/2 = X/2
Now, he gave ⅓ of remaining part of property to charity, i.e., ⅓×[x/2]
=x/6
And, rest part of his property he gave to his wife, i.e., (x/2)-(x/6)
=x/3
Since, the charity amount is Rs. 1,00,000.
Therefore, x/6 = Rs.1,00,000
Or x= Rs.6,00,000
This, total amount property =Rs.6,00,000
Hence, Mr. Mathews's wife gets
= Rs. (6,00,000÷3)
= Rs. 2,00,000.