Asked by Anonymous

How many molecules are there in 985 mL of nitrogen at 0.0 degrees C and 1.00x10^-6 mmHg?

3.50 molecules
Answered by DrBob222
The digits are close but the 10^? is missing.
Answered by Anonymous
3.50x10^23 molecules
Answered by DrBob222
I don't like that answer either. Post your work and let me find the error.

By the way, the 12 atm to 25 atm problem below is OK but the site will not let me post an OK.
Answered by Anonymous
This is my work:

985mLN / 1000 = .985 L
0.0 degrees C + 273 = 273 K
1.00x10^-6 mmHg / 760 mmHg = 1.32 atm
1.32 atm x .985 L = n ( .08206 Latm / molK)x273K

n = .0580 moles x 6.022x10^23 = 3.50 x 10^23 molecules.

Ok thanks
Answered by DrBob222
985mLN / 1000 = .985 L
0.0 degrees C + 273 = 273 K

1.00x10^-6 mmHg / 760 mmHg = 1.32 atm <b>YOU forgot the 10^-6</b>

1.32 atm x .985 L = n ( .08206 Latm / molK)x273K

n = .0580 moles x 6.022x10^23 = 3.50 x 10^23 molecules.

<b>For digits I obtained 3.48; the difference is that you rounded the 1.315 to 1.32 while I left all of that in the calculator and made all of it as one calculation. It appears you made three calculations.</b>
Answered by DrBob222
Also 1.00/760 is not 1.32 but 1.32E-3.
Thus 1E-6/760 = 1.32E-9 I think.
Answered by Anonymous
Ok thanks!
Answered by Anonymous
How many molecules are there in 985 mL of nitrogen at 17.0° C and1.00 x 10^-6 mm Hg?
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