Asked by David soye
a piece of metal of density
7800kgm-3 weighs 20N in air. Cal. The
apparent weight of th metal when
completely immersed in a liquid of density 830kgm-3
7800kgm-3 weighs 20N in air. Cal. The
apparent weight of th metal when
completely immersed in a liquid of density 830kgm-3
Answers
Answered by
Damon
20 N = 9.81 * m
m = 2.04 kg
volume = 2.04 kg/7800 kg/m^3
= .000261 m^3
mass of fluid displaced = .000261*830
= .217 kg
mass metal - mass fluid displaced = 1.82 kg metal mass
metal weight = m g = 1.82*9.81 = 17.9 Newtons
m = 2.04 kg
volume = 2.04 kg/7800 kg/m^3
= .000261 m^3
mass of fluid displaced = .000261*830
= .217 kg
mass metal - mass fluid displaced = 1.82 kg metal mass
metal weight = m g = 1.82*9.81 = 17.9 Newtons
Answered by
Anonymous
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EZEKIEL
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Answered by
JAMES
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