Asked by Anonymous
Use the following data
2C(s) + 4H2(g) --> C3H8(g)
DH= -103.85 kJ/molrxn
C(s) + O2(g) --> CO2(g)
DH= -393.51 kJ/molrxn
H2(g) + 1/2O2(g) --> H2O(g)
DH= -241.82 kJ/molrxn
to calculate the heat of combustion of propane, C3H8
C3H8(g) + 5O2(g) --3CO2(g) + 4H20(g)
2C(s) + 4H2(g) --> C3H8(g)
DH= -103.85 kJ/molrxn
C(s) + O2(g) --> CO2(g)
DH= -393.51 kJ/molrxn
H2(g) + 1/2O2(g) --> H2O(g)
DH= -241.82 kJ/molrxn
to calculate the heat of combustion of propane, C3H8
C3H8(g) + 5O2(g) --3CO2(g) + 4H20(g)
Answers
Answered by
DrBob222
You have a typo in #1, that should be 3C(s).
Reverse #1, add to 3x #2, and to 4x #3.
Reverse #1, add to 3x #2, and to 4x #3.
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