Asked by destiny
You add 8950 J of heat to 174 g of iron. What is the temperature increase of the iron (c = 452 J/(kg • C°))?
Answers
Answered by
Damon
8950 J = .174 kg (delta T)[452 J/(kg deg C)]
so
delta T = 8950 /(.174*452)
so
delta T = 8950 /(.174*452)
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