Asked by Zenny
R and S are two observation posts on the same horizontal ground as the foot P of a vertical tower PQ.The tower is 18m due north of S and 24m east of R.The angle of elevation of Q from S is 35degree.calculate the height pQ,the distance RS,the angle of elevation of Q from S and bearin of R from S.
Answers
Answered by
Steve
As always, draw a diagram. You can then see that
PQ/18 = tan35°
RS^2 = 18^2+24^2
I don't know which is the typo, but you have angle of Q from S twice.
Anyway, use the tan function to get the other angle, as I did above, but this time you know PQ, and have to get the angle.
The bearing of R from S is N θ W where tanθ = 24/18
or, just using a single direction, 360°-arctan(24/18)
PQ/18 = tan35°
RS^2 = 18^2+24^2
I don't know which is the typo, but you have angle of Q from S twice.
Anyway, use the tan function to get the other angle, as I did above, but this time you know PQ, and have to get the angle.
The bearing of R from S is N θ W where tanθ = 24/18
or, just using a single direction, 360°-arctan(24/18)
Answered by
Anonymous
The diagrams
Answered by
temmytop
I want the illustration diagram of that problem
Answered by
[email protected]
I want the illustration diagram of the above solved problem.
Answered by
Estar
I think diagrams are necessary.
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