An apple (0.100 kg) is thrown vertically upward at a speed of [let x = any whole number between 10 and 20] m/s (from an arm 1.5 m off of the ground). What is the maximum height that the apple reaches? (g=9.8 m/s2)

Answer 1

Vf^2 = Vo^2 + 2g*h = 0.
h = -Vo^2/2g + 1.5 = Meters above gnd.
Vo = 20 m/s.
g = -9.8 m/s^2.