Asked by Erinne
A rifle is aimed horizontally at a target 50m away. The bullet hits the target 2.0cm below the aim point.
A. What was the bullet's fight time?
B. What was the bullet's speed as it left the barrel?
A. What was the bullet's fight time?
B. What was the bullet's speed as it left the barrel?
Answers
Answered by
bobpursley
see above.
Answered by
TJ
To get the time use this:
T=(sqrt)of (2(.027m)/g
Now initial velocity formula:
V=d/t
V=52/.074=700.51-701m/s
T=(sqrt)of (2(.027m)/g
Now initial velocity formula:
V=d/t
V=52/.074=700.51-701m/s
Answered by
Anonymous
700
Answered by
hy
wrong
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