Asked by Denielle
A varies as the square of B and inversly as C. When A is 6 B is 5 and C is 100.
Calculate A when B is 12 and C is 72.
Calculate A when B is 12 and C is 72.
Answers
Answered by
Steve
A = kB^2/C
So, AC/B^2 = k and is constant.
So, you want A such that
72A/144 = 6*100/25
So, AC/B^2 = k and is constant.
So, you want A such that
72A/144 = 6*100/25
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