Starting from 130 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is traveling as a constant rate of 25 feet per second. The distance between the bicycle and the checkpoint is given by the equation d=|130-25t|. At what times is the bike 15 feet away from the checkpoint.

Question

a. 4.6 sec and 9.2 sec
b. 2.9 sec and 5.8 sec
c. 4.6 sec and 5.8 sec
d. 2.9 sec and 3.3 sec

Answer 1

how long does it take to go the 130 ft?
130/25 = 5.2 sec

How long to go 15 ft?
0.6 sec

So, at 5.2±0.6 the distance will be 15 ft

Now what do you think?

Answer 2

is it a or c i don't understand what the second part means 5.8 seconds or 9.2 seconds?

Answer 3

It's c

Answer 4

Thanks Nunya!

Answer 5

ABDCDDBCThe answer is c . Thank me later