Asked by rayanne
A 0.78 kg rock is whirled around in a flat circle at the end of a string of length 64 cm and a radial acceleration of 3.70 m/s^2 (a) What is the linear velocity of string? (b) what is the centripetal force acting on the rock?
Vm= sqrt( grFs )
= sqrt( 9.8 m/s)(47.5m) (0.740)
?
Vm= sqrt( grFs )
= sqrt( 9.8 m/s)(47.5m) (0.740)
?
Answers
Answered by
Damon
Ac = v^2/R = 3.70
v^2 = 3.7 * 0.64
solve for v
F = m Ac = 0.78 * .70
v^2 = 3.7 * 0.64
solve for v
F = m Ac = 0.78 * .70
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