Asked by starmario12
A parallelogram has adjacent sides 7 cm and 15 cm. If the shorter diagonal is 10 cm long, find the length of the longer diagonal.
Answers
Answered by
Steve
using the law of cosines, we know that
7^2+15^2-2*7*15 cosθ = 10^2
cosθ = (7^2+15^2-10^2)/(2*7*15) = 29/35
So, that means the other diagonal, x is
x^2 = 7^2+15^2+2*7*15*29/35 = 448
x = 8√7
7^2+15^2-2*7*15 cosθ = 10^2
cosθ = (7^2+15^2-10^2)/(2*7*15) = 29/35
So, that means the other diagonal, x is
x^2 = 7^2+15^2+2*7*15*29/35 = 448
x = 8√7
Answered by
Anonymous
A parallelogram has adjacent sides 8 cm and 13cm. If the shorter diagonal is 11 cm long, find the length of the longer diagonal.
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