Asked by Anonymous
The length of a rectangle is three times its width.
If the area of the rectangle is
108 yd^2, find its perimeter.
If the area of the rectangle is
108 yd^2, find its perimeter.
Answers
Answered by
Steve
w*3w = 108
so, w=6
p = 2(w+3w) = ?
so, w=6
p = 2(w+3w) = ?
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