mols Na2CO3 = M x L = ?
Using the coefficients in the balanced equation, convert mols Na2CO3 to mols HNO3.
Now M HNO3 = mols HNO3/L HNO3 solution.
You know M and mols, solve for L and convert to mL.
What volume (in mL) of a 0.300 M HNO3 solution will completely react with 43.9 mL of a 0.146 M Na2CO3 solution according to this balanced chemical equation?
Na2CO3(aq)+2 HNO3(aq)->2 NaNO3(aq)+CO2(g)+H20(l)
1 answer