Asked by Anna
A mystery surprise box is sliding down a ramp at a constant speed. The box has a mass of 55.0kg and the ramp makes a 40.0œ angle with the horizontal. What is the coefficient of kinetic friction between the box and the ramp?
Please help asap. Thank you.
Please help asap. Thank you.
Answers
Answered by
Henry
Wb = M*g = 55 * 9.8 = 539 N.
Fp = 539*sin40 = 347 N. = Force parallel
to the ramp.
Fn = 539*Cos40 = 413 N. = Normal force.
Fp-Fk = M*a.
347-Fk = M*0 = 0.
Fk = 347 N. = Force of kinetic friction.
u = Fk/Fn.
Fp = 539*sin40 = 347 N. = Force parallel
to the ramp.
Fn = 539*Cos40 = 413 N. = Normal force.
Fp-Fk = M*a.
347-Fk = M*0 = 0.
Fk = 347 N. = Force of kinetic friction.
u = Fk/Fn.
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