Asked by Sara
If four times the square of a positive number is added to the product of -29 and the number, the result is 63. Find the number
Answers
Answered by
Jai
Let x be the number.
Write everything in math expression using x.
Four time the square of a number: 4x^2
Is added to the product of -29 and the number: + (-29)x
The result is 63: = 63
Combining them, we have
4x^2 + (-29)x = 63
or
4x^2 - 29x - 63 = 0
We have a quadratic equation here. Good thing is, it's factorable:
(4x + 7)(x - 9) = 0
4x + 7 = 0
x = -7/4
x - 9 = 0
x = 9
Since in the problem, the number is 'positive', we take x = 9.
Hope this helps~ `u`
Write everything in math expression using x.
Four time the square of a number: 4x^2
Is added to the product of -29 and the number: + (-29)x
The result is 63: = 63
Combining them, we have
4x^2 + (-29)x = 63
or
4x^2 - 29x - 63 = 0
We have a quadratic equation here. Good thing is, it's factorable:
(4x + 7)(x - 9) = 0
4x + 7 = 0
x = -7/4
x - 9 = 0
x = 9
Since in the problem, the number is 'positive', we take x = 9.
Hope this helps~ `u`
Answered by
Sara
Thank you this makes sense now!
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