Asked by ThomasTheTrain
If the polynomial x^3+6x^2+11x+6 expresses the volume, in cubic inches, of the box, and the width is (x+1)in., what are the dimensions of the box?
I need to answer the question in long dvision or synthetic division, the thing is i have no idea how to do either of those.
quick explanation?
I need to answer the question in long dvision or synthetic division, the thing is i have no idea how to do either of those.
quick explanation?
Answers
Answered by
ThomasTheTrain
Am i capable of taking this question down? no one answered and ive gotten the information i needed from other sources.
Answered by
Steve
a little synthetic division quickly shows that
x^3+6x^2+11x+6 = (x+1)(x^2+5x+6) = (x+1)(x+2)(x+3)
x^3+6x^2+11x+6 = (x+1)(x^2+5x+6) = (x+1)(x+2)(x+3)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.