Sure! To solve this problem, you can use the following equation:
q = n * ΔHvap
where:
q = heat energy (in kJ)
n = number of moles
ΔHvap = molar heat of vaporization (in kJ/mol)
First, we need to determine the number of moles of ethanol that can be boiled with the given heat energy. We can rearrange the equation and solve for n:
n = q / ΔHvap
Substituting the given values:
n = 343.0 kJ / 38.6 kJ/mol
n ≈ 8.88 moles
Now that we have the number of moles, we can convert this to grams using the molar mass of ethanol:
m = n * M
where:
m = mass of ethanol (in grams)
M = molar mass of ethanol (in g/mol)
The molar mass of ethanol is 46.07 g/mol (2 * 12.01 g/mol for carbon + 6 * 1.01 g/mol for hydrogen + 1 * 16.00 g/mol for oxygen). Now we can calculate the mass of ethanol:
m = 8.88 moles * 46.07 g/mol
m ≈ 409.1 g
So, approximately 409.1 grams of ethanol can be boiled with 343.0 kJ of heat energy.
How many grams of ethanol, C2H5OH, can be boiled with 343.0 kJ of heat energy? The molar heat of vaporization of ethanol is 38.6 kJ/mol
I'm not sure how I am supposed to set this problem up. Can someone help me, please?
1 answer