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A GREAT PYRAMID HAS A SQUARE BASE 230M ON EACH SIDE. THE 4 TRIANGULAR FACES EACH MAKE AN ANGLE OF 51.50' WITH THE GROUND.
1) HOW TALL IS THE PYRAMID ?
2) WHAT ARE THE DIMENSIONS OF EACH OF THESE TRIANGULAR FACES ?
1) HOW TALL IS THE PYRAMID ?
2) WHAT ARE THE DIMENSIONS OF EACH OF THESE TRIANGULAR FACES ?
Answers
Answered by
Steve
the center of the pyramid is 115m from each edge. Find the height h using
h/115 = tan51°50'
Now figure the slant height s, using
s^2 = 115^2+h^2
The isosceles triangles thus have base 230 and altitude s.
The edges of the pyramid(the equal sides of the triangles) have length x, where
x^2 = s^2+115^2
h/115 = tan51°50'
Now figure the slant height s, using
s^2 = 115^2+h^2
The isosceles triangles thus have base 230 and altitude s.
The edges of the pyramid(the equal sides of the triangles) have length x, where
x^2 = s^2+115^2
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