Asked by beverly

3NO2(g) + H2O(l) → 2HNO3(l) + NO(g)



How many moles of nitric acid are produced starting from 5.00 moles of NO2(g) and excess water?
Answered by Damon
mols HNO3/ mols NO2 = 2/3

so (2/3)5 = 10/3
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