Asked by jecce.
can someone check these for me ?
Lead(IV)nitrate-- Pb(No3)4
Aluminumoxide-- Al2O
Ammoniumphosphate-- NH4(Po4)
Perchloric Acid-- Clo4
Copper(II)bromide-- CuBr2
Thankss!
Lead(IV)nitrate-- Pb(No3)4
Aluminumoxide-- Al2O
Ammoniumphosphate-- NH4(Po4)
Perchloric Acid-- Clo4
Copper(II)bromide-- CuBr2
Thankss!
Answers
Answered by
bobpursley
yes, no, no, no, yes.
Answered by
jecce.
Ugh.
Why is 2,3, and 4 wrong?
Why is 2,3, and 4 wrong?
Answered by
DrBob222
Oxidation state of Al is +3, O is -2.
NH4 is +1, PO4 is -3
NH4 is +1, PO4 is -3
Answered by
DrBob222
HClO4 is perchloric acid
The series is
HClO4
HClO3
HClO2
HClO
HCl
The series is
HClO4
HClO3
HClO2
HClO
HCl
Answered by
jecce.
so im still confused.
The answer would be then, Al3O2?
and
NH4(Po4)3
The answer would be then, Al3O2?
and
NH4(Po4)3
Answered by
Eve
Why is methyl and ethyl groups called hydrocarbons
Answered by
DrBob222
You should post your questions under Post a New Question located at the top of the page. Posting as a piggy back on another post often gets ignored if we don't go back to look to see if there is a follow up question. methyl and ethyl groups are CH3 and CH3CH3. The have hydrogen and carbon; thus they are hydrocarbons.
Answered by
DrBob222
Yes, you are. One was of checking to see if your answer is correct is to add up the oxidations states of everything. All compounds must add to zero. Does Al3O2 add to zero. Al is 3x+3=+9 and O is 2 x -2 = 4. Nope. Doesn't add to zero. Here is how you do it.Write AlO
Above Al write +3. Above O write -2.
For the subscripts, draw an X starting at the top of the l and ending at the bottom of the O. The other leg of the X starts at the top of the O and moves to the left and downward to the bottom of the l. Now, just place those numbers at the bottom of the two legs of the X. Thus, Al2O3. Ignore the signs. Check it?
Al = 2x+3 = +6.
O = 3x -2 = -6
+6 and -6 = 0. Voila!
NH4 is +1
PO4 is -3
(NH4)3PO4 or to make it look nicer, if I can do it,
(NH<sub>4</sub>)<sub>3</sub>PO<sub>4</sub>
Above Al write +3. Above O write -2.
For the subscripts, draw an X starting at the top of the l and ending at the bottom of the O. The other leg of the X starts at the top of the O and moves to the left and downward to the bottom of the l. Now, just place those numbers at the bottom of the two legs of the X. Thus, Al2O3. Ignore the signs. Check it?
Al = 2x+3 = +6.
O = 3x -2 = -6
+6 and -6 = 0. Voila!
NH4 is +1
PO4 is -3
(NH4)3PO4 or to make it look nicer, if I can do it,
(NH<sub>4</sub>)<sub>3</sub>PO<sub>4</sub>
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