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Original Question
Laura drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 6 hours. When Laura drov...Asked by Roger
Austin drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took
8 hours. When Austin drove home, there was no traffic and the trip only took
5 hours. If his average rate was
21 miles per hour faster on the trip home, how far away does Austin live from the mountains?
Do not do any rounding.
8 hours. When Austin drove home, there was no traffic and the trip only took
5 hours. If his average rate was
21 miles per hour faster on the trip home, how far away does Austin live from the mountains?
Do not do any rounding.
Answers
Answered by
Reiny
speed on first leg ---- x mph
speed on return trip -- x+21 mph
distance on first leg = 8x
distance for return leg = 5(x+21)
but the distances are equal, so
8x = 5(x+21)
8x = 5x + 105
3x=105
x = 35
distance = 8(35) = 280 miles
speed on return trip -- x+21 mph
distance on first leg = 8x
distance for return leg = 5(x+21)
but the distances are equal, so
8x = 5(x+21)
8x = 5x + 105
3x=105
x = 35
distance = 8(35) = 280 miles
Answered by
Reiny
Just realized I did this same question a few weeks back
http://www.jiskha.com/display.cgi?id=1443062344
http://www.jiskha.com/display.cgi?id=1443062344