Asked by XOXOX
Calvin is pulling Hobbes on his sled across level ground with a force of 25 N [30o above the ground]. They start with a speed of 1 m/s. The mass of Hobbes and the sled is 14 kg and the coefficient of friction between the sled and the ground is 0.15. If Calvin pulls Hobbes for 18 m, determine
d) the final speed of Hobbes and the sled
d) the final speed of Hobbes and the sled
Answers
Answered by
Henry
Fs = M*g = 14 * 9.8 = 137 N.
Fp = 137*sin 0 = 0 = Force parallel to the gnd.
Fn = 137*Cos 0 - 25*sin30 = 124.5 N. = Normal Force.
Fk = u*Fn = Force of kinetic friction.
a = (25*Cos30-Fp-Fk)/M.
Vf^2 = Vo^2 + 2a*d
Vo = 1 m/s.
d = 18 m.
Vf = ?
Fp = 137*sin 0 = 0 = Force parallel to the gnd.
Fn = 137*Cos 0 - 25*sin30 = 124.5 N. = Normal Force.
Fk = u*Fn = Force of kinetic friction.
a = (25*Cos30-Fp-Fk)/M.
Vf^2 = Vo^2 + 2a*d
Vo = 1 m/s.
d = 18 m.
Vf = ?
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